x^2+4x=53=0

Solution for x^2+4x=53=0 equation:

x^2+4x=53=0

We move all terms to the left:

x^2+4x-(53)=0

a = 1; b = 4; c = -53;
Δ = b2-4ac
Δ = 42-4·1·(-53)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{57}}{2*1}=\frac{-4-2\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{57}}{2*1}=\frac{-4+2\sqrt{57}}{2}
$